9x^2+50x-4=0

Solution for 9x^2+50x-4=0 equation:

9x^2+50x-4=0

a = 9; b = 50; c = -4;
Δ = b2-4ac
Δ = 502-4·9·(-4)
Δ = 2644
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2644}=\sqrt{4*661}=\sqrt{4}*\sqrt{661}=2\sqrt{661}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-2\sqrt{661}}{2*9}=\frac{-50-2\sqrt{661}}{18}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+2\sqrt{661}}{2*9}=\frac{-50+2\sqrt{661}}{18}
$